Senin, 13 Februari 2012

Segmentasi IP

Tugas Magang

1.      Ada 18 komputer dalam 2 ruangan. Menggunakan /27 dan 30 ip. Carilah network address, broadcast, jumlah ip yang bisa dipakai, dan total ip ! 
Jawab  :          
·         /27  =  224
·         Warnet pertama = 192.168.10.0 – 192.168.10.31  
·         Jadi network address = 192.168.10.0
·         Broadcast = 192.168.10.31
·         Jumlah IP yg bisa dipakai = 30
·         Total IP = 32  

·         Warnet kedua = 192.168.10.32
·         Network IP = 192.168.32
·         Broadcast = 192.168.10.63
·         Jumlah IP yang bisa dipakai = 30

2.      Diketahui  : 
·         Network IP = 192.168.14.0/29
·         Dibagi 3 departement : IT, Finance, dan Sales
·         PC masing-masing departement 5unit
   
Ditanya    :  
·         Berapa segmentasi IP yang digunakan ?
·         Subnet mask ?
·         Broadcast address ?
·         IP yang digunakan ?

Jawab  : 
-         Segmentasi IP masing-masing = 192.168.50.0/29
-         Subnet mask = 255.255.255.248


  •       IT    
-                            Network address = 192.168.50.0
-                            Broadcast = 192.168.50.7
-                            Start IP = 50.1 - 50.6
  •      Finance  : 
-                            Network address = 192.168.50.8
-                            Broadcast = 192.168.50.15
-                            Start IP = 50.9 – 50.14
  •       Sales  :
-                            Network address = 192.168.50.16
-                            Broadcast = 192.168.50.23
-                            Star IP = 50.17 – 50.22







                 














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